y=5/(2*x^2+1)

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Solution for y=5/(2*x^2+1) equation:


D( x )

2*x^2+1 = 0

2*x^2+1 = 0

2*x^2+1 = 0

2*x^2 = -1 // : 2

x^2 = -1/2

x in (-oo:+oo)

y = 5/(2*x^2+1) // - 5/(2*x^2+1)

y-(5/(2*x^2+1)) = 0

y-5*(2*x^2+1)^-1 = 0

y-5/(2*x^2+1) = 0

(y*(2*x^2+1))/(2*x^2+1)-5/(2*x^2+1) = 0

y*(2*x^2+1)-5 = 0

2*x^2*y+y-5 = 0

(2*x^2*y+y-5)/(2*x^2+1) = 0

(2*x^2*y+y-5)/(2*x^2+1) = 0 // * 2*x^2+1

2*x^2*y+y-5 = 0

2*x^2*y = -(y-5) // : 2*y

x^2 = (5-y)/(2*y)

x^2 = (5-y)/(2*y) // ^ 1/2

abs(x) = ((5-y)^(1/2))/(2^(1/2)*y^(1/2))

x = ((5-y)^(1/2))/(2^(1/2)*y^(1/2)) or x = -(((5-y)^(1/2))/(2^(1/2)*y^(1/2)))

x in { ((5-y)^(1/2))/(2^(1/2)*y^(1/2)), -(((5-y)^(1/2))/(2^(1/2)*y^(1/2))) }

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